Mexican boxer vows to KO 'Boom-Boom'

source | abs-cbnNEWS.com | MANILA, Philippines - Mexican fighter Miguel Angel Mendoza is guaranteeing a knockout victory when he faces Filipino boxer Rey "Boom-Boom" Bautista this Saturday at "Pinoy Pride X."

Mendoza is undefeated through 17 fights, with all bouts being won via knockout. He is aiming to add Bautista (31-2, 23 KOs) to his list of his victims.

"I came to Cebu to fight, I will deliver a knockout," Mendoza said in an interview with PhilBoxing.com. "I will knock him out in six rounds." [http://philboxing.com/news/story-63825.html]

Mendoza revealed that he has watched videos of Bautista and admitted that the Filipino featherweight is a complete, fast fighter.

"But I know how to look for openings," he added.

Bautista, who will be defending his IBF International Featherweight belt, is hoping that a win over Mendoza will push him towards contention for a shot at a world title.

Mendoza is aiming to disrupt Bautista's plans, saying he will go strong against the Filipino and exchange punches with him.

"It will be a hard fight, but not the hardest of my career," he said, adding that he has already fought strong Mexican fighters.

"Pinoy Pride X" will be shown on ABS-CBN on Sunday, December 11 starting 10:15 a.m.

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